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Neco 2024 Chemistry Questions & Answers (June/July Exam)

Welcome to “Naijaclass Academy” For Neco 2024 Chemistry Questions & Answers (June/July Exam)

Monday, 15th July 2024 Chemistry (Objective & Essay) 10:00am – 1:00pm

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CHEMISTRY OBJ 1-10: BBCCAEDECE 11-20: DDBCADEEAD 21-30: ACADCDDBAE 31-40: CCBCECACBA 41-50: CCBDCAEBBA 51-60 BBDDCACBCC =================================================

ANSWER FOUR(4) QUESTIONS ONLY

(1a) (i) Hydrogen gas is colorless and odorless. (ii) Hydrogen is highly flammable, which means it can easily catch fire when exposed to a flame or spark. (iii) Hydrogen gas has low density, making it lighter than air.

(1b) (I) Group 17 (halogens) (II) lodine (III) lodine

(1ci) I. Calcium (Ca²⁺) II. Magnesium (Mg²⁺)

(1cii) I. lon exchange method II. Lime-soda method

(1di) (I) Methyl orange is used in the titration of a strong acid with a strong base. (II) Phenolphthalein is used in the titration of a strong base with a strong acid.

(1dii) (I) Hydrated salt: Copper(II) sulfate pentahydrate (CuSO₄.5H₂O) (II) Acidic salt: Ammonium chloride (NH₄Cl) (III) Basic salt: Sodium carbonate (Na₂CO₃)

(1ei) 2-methylbutane >>> pentane >>> 2,2-dimethylpropane

(1eii) (I) 1-bromo-3-methylbutane (II) 2-methylpentane

(1eiii) Benzene is used as a starting material in the production of various important chemicals such as ethylbenzene, cumene, cyclohexane, and nitrobenzene.

(1eiv) Saponification is a process in which ester molecules are hydrolyzed in the presence of a strong base (such as sodium hydroxide or potassium hydroxide) to form alcohol and the salt of the carboxylic acid.

(1f) Given, Vapour density = 77

molecular mass of XCl₄ = Molecular mass = Vapour density x 2 = 77 x 2 = 154

Molecular mass of XCl₄ = X + 4(Atomic mass of Cl) 154 = X + 4(35.5) X = 154 – 142 X = 12

:. The relative atomic mass of X is 12.

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(2ai) A molar solution (M) is a solution that contains one mole of solute (dissolved substance) per liter (dm³) of solution.

(2aii) Convert volume from cm³ to dm³: 250cm³=0.250dm³

Number of moles of Na₂CO₃ = Concentration(mol/dm³) × Volume (dm³) = 0.10mol/dm³ x 0.25 dm³ = 0.025mol

Mass of Na₂CO₃ = Number of moles x Molar mass(g/mol) = 0.025 mol x 106 g/mol = 2.65 g

(2bi) (i) K > 1: Indicates that, at equilibrium, the concentration of the products is greater than the concentration of the reactants. The reaction favors the formation of products. (ii) K < 1:Indicates that, at equilibrium, the concentration of the reactants is greater than the concentration of the products. The reaction favors the formation of reactants. (iii) K = 1: Indicates that, at equilibrium, the concentrations of reactants and products are equal. Neither the reactants nor the products are favored.

(2bii) (i) Temperature: Increasing temperature can shift the equilibrium position depending on whether the reaction is endothermic or exothermic. (ii) Pressure: For reactions involving gases, changing the pressure can affect the equilibrium position. (iii) Concentration: Altering the concentration of reactants or products can shift the equilibrium.

(2ci) (I) Strong acids completely dissociate in water, while weak acids partially dissociate (II) Strong acids have a high tendency to donate protons, whereas weak acids have a lower tendency

(2cii) (I) Covalent compounds have low melting and boiling points (II) They are generally insoluble in water (III) Covalent compounds tend to be soft and brittle.

(2dii) The monosaccharides contained in sucrose are glucose and fructose.

(2diii) (I) Temperature: High temperatures can cause proteins to unfold and lose their functional shape. (II) pH Levels: Extreme pH levels (either too acidic or too basic) can disrupt the hydrogen and ionic bonds that maintain a protein’s structure. ================================================

(3ai) (i) Stage 1: Production of sulfur dioxide: S(s) + O₂(g) ==> SO₂(g)

(ii) Stage 2: Conversion of sulfur dioxide to sulfur trioxide: 2SO₂(g) + O₂(g) <==> 2SO₃(g)

(iii) Stage 3: Absorption of sulfur trioxide in water to form tetraoxosulphate (VI) acid: SO₃(g) + H₂O(l) ==> H₂SO₄(l)

(3aii) (i) Temperature: Increasing the temperature can increase the rate of reaction by providing more kinetic energy to the molecules involved. However, this may not always favor the equilibrium position. (ii) Pressure: For gaseous reactions, increasing the pressure can shift the equilibrium towards the side with fewer moles of gas molecules. (iii) Concentration: Higher concentrations of reactants can increase the rate of reaction, but it may not affect the position of equilibrium.

(3aiii) (i) Relative positions of ions in the electrochemical series. (ii) Concentration of ions in the electrolyte solution. (iii) Nature of the electrodes.

(3b) Molar mass of MgSO₄= Mg + S +4 * O Molar mass of MgSO₄= 24 + 32 + (4*16) = 24+32+64= 120g/mol

The molar concentration in mol/dm³= 0.75mol/dm³

Given the mass concentration of the hydrated salt= 184.5g/dm³

Mass concentration=molar concentration * molar mass of MgSO₄⋅XH₂O 184.5 = 0.75 * molar mass of MgSO₄⋅XH₂O Molar mass of MgSO₄⋅XH₂O= 184.5/0.75 = 246g/mol

Molar mass of MgSO₄⋅XH₂O= molar mass of MgSO₄ + X * molar mass of H₂O

246 = 120 + X * (2*1+16) 246 = 120 + X * 18 246 = 120 + 18X X = (246 – 120)/18 X = 126/18 X = 7

(3ci) Reduction refers to the process where an atom, ion, or molecule gains electrons, leading to a decrease in its oxidation number.

(3cii) The oxidizing agent in the reaction is Br₂

(3ciii) (I) Contain carbon-hydrogen bonds. (II) Often have covalent bonding. (III) Can be highly complex in structure.

(3civ) (I) Plants (e.g., olive oil, sunflower oil) (II);Animals (e.g., butter, lard) ============================================

(4ai) Allotropy is the existence of two or more different forms of the same element in the same physical state.

(4aii) Carbon

(4aiii) (I) It is used in carbonated beverages to provide fizziness. (II) It is used in fire extinguishers as it is denser than air and can displace oxygen, thereby suffocating the fire.

(4bii) Calcium reacts with oxygen to form calcium oxide (CaO): 2Ca + O₂ ==> 2CaO

Molar mass of calcium: 40g/mol Molar mass of oxygen: 16g/mol

Number of moles of Ca = 4.8g/40g/mol = 0.12mol

Number of moles of O₂ = 0.12mol (since it’s a 1:1 ratio)

Mass of oxygen required = 0.12mol x 16g/mol = 1.92g

(4ci) (I) X is Iron(III) oxide (Fe₃O₄) and Y is Hydrogen gas (H₂) (II) Equation: 3Fe + 4H₂O ==> Fe₃O₄ + 4H₂

(4cii) Yellow color (lead iodide, PbI₂)

(4ciii) Diagram

(4di) Nitrogen prepared from air is often denser than pure nitrogen because it contains impurities, mainly argon and small amounts of other gases. These impurities increase the overall mass per unit volume of the gas mixture compared to pure nitrogen, making it denser. When nitrogen is extracted from the air, it is typically around 99.9% pure, but that 0.1% of impurities, such as argon, oxygen, and trace gases, can still affect its density.

(4dii) Percentage composition of sodium in NaNO₃: Percentage of an element = (Atomic mass of the element * Number of atoms of the element/molecular mass of the compound) * 100

Molar mass of NaNO₃: Na: 23g/mol N: 14g/mol O: 16g/mol * 3 = 48g/mol

= 23 + 14 + 48 = 85 g/mol

Percentage of Na: (Mass of Na / Molar mass of NaNO₃) x 100% = (23/85) * 100 = 0.2706 x 100 = 27.06%

(4diii) (I) Ammonia (NH₃): Heavy chemical (II) Drugs: Fine chemicals (III) Sodium hydroxide (NaOH): Heavy chemical ===========================================

(5ai) (I) A is NH₃ (Ammonia) and B is HCl (Hydrochloric acid). (II) Decomposition reaction

(5aii) (I) All members of a homologous series have the same functional group, which gives them similar chemical properties. (II) There is a gradual change in physical properties (such as boiling point, melting point, and solubility) as the molecular mass increases.

(5aiii) (I) lonic bond (II) Covalent bond (III) Metallic bond

(5bi) (I) Anhydrous Copper(II) Sulfate (CuSO₄) (II) Cobalt(II) Chloride Paper (CoCl₂)

(5bii) (I) Ensure the burette is calibrated correctly (II) Use a white tile or paper to read the meniscus clearly (III) Take readings with the eye level at the meniscus

(5ci) (I) Atomic radius: -Across the Period: Atomic radius decreases from left to right across a period. This is because the number of protons in the nucleus increases, pulling the electrons closer to the nucleus due to stronger electrostatic attraction. -Down the Group: Atomic radius increases down a group. This is because additional electron shells are added, making the atom larger despite the increase in nuclear charge.

(II) Ionization energy: -Across the Period: Ionization energy increases from left to right across a period. This is due to the increasing nuclear charge, which holds the electrons more tightly and requires more energy to remove one. -Down the Group: Ionization energy decreases down a group. As the atomic radius increases, the outer electrons are farther from the nucleus and are less strongly attracted, making them easier to remove.

(5cii) (I) Potassium (K): 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ (II) Magnesium (Mg): 1s² 2s² 2p⁶ 3s² (III) Oxygen (O): 1s² 2s² 2p⁴

(5di) (I) H⁺ (hydronium ion) (II) H₃O⁺ (hydronium ion)

(5dii) A physical change is a change in which the substance undergoes a change in state or form, but its chemical composition remains the same. Examples include melting, freezing, boiling, condensation, and sublimation. ===========================================

(6ai) Ethene: C₂H₄ has a double bond between two carbon atoms. Ethyne: C₂H₂ has a triple bond between two carbon atoms.

(6aii) Polyacetylene

(6aiii) Structure of Polyethylene: (-CH=CH-)n

(6bi) (I) Fehling’s solution added to reducing sugar: Precipitate formation (red precipitate indicates presence of reducing sugar) (II) Millon’s reagent added to protein: White precipitate formation (indicating presence of protein) (III) Sodium metal dropped into ethanol: Vigorous reaction, flame, and formation of sodium ethoxide

(6bii) Solubility of KCIO (potassium hypochlorite): Molar mass of KCIO₃: 39 + 35.5 + (3*16) = 122.5g/mol

Convert mass of KCIO₃ to moles = 4.9/122.5 = 0.04mol

Volume of water = 20cm³ = 0.02dm³

Solubility S in mol/dm³ = moles of KCIO₃/Volume of water in dm³ = 0.04/0.02 Solubility= 2.0mol/dm³

(6ci) (I) It is a colorless liquid at room temperature. (II) It has a characteristic odor. (III) It is miscible with water in all proportions.

(6cii) Equations for preparation of ethanol from ethene: (I) C₂H₄ + H₂O ==> C₂H₅OH (hydration reaction) (II) C₂H₄ + H₂SO₄ ==> C₂H₅HSO₄ (sulfonation reaction) (III) C₂H₅HSO₄ + H₂O ==> C₂H₅OH + H₂SO₄ (hydrolysis reaction)

(6di) (I) It is used in the manufacture of glass. (II) It is used in water softening and as a cleaning agent.

(6dii) (I) They often exhibit variable oxidation states. (II) They form colored compounds and ions. (III) They have catalytic properties due to their ability to adopt multiple oxidation states and their surface structures.

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NECO Chemistry Questions and Answers 2023/2024 (Essay and Objectives)

NECO Chemistry Questions and Answers 2023. I will be showing you past Chemistry objectives and theory repeated questions for free in this post. You will also understand how NECO Chemistry questions are set and how to answer them.

The National Examinations Council (NECO) is an examination body in Nigeria that conducts the Senior Secondary Certificate Examination and the General Certificate in Education in June/July and December/January respectively.

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NECO Chemistry Objectives and Essay Answers 2023 (Expo)

The 2023 NECO Chemistry expo will be posted here today 24th July during the NECO Chemistry examination. Keep checking and reloading this page for the answers.

NECO 2023 Chemistry Answers Loading.

OBJ Answers:

1-10: DEADADECAD

11-20: BAEDDBDBAE

21-30: CCDCABDDCD

31-40: EBEECEBCEE

41-50: BCCECDDADD

51-60: DABBDEAECA

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NECO Chemistry Questions and Answers For Practice

The following NECO Chemistry questions are questions to expect in the 2023 NECO examination.

1. The minimum amount of energy required for effective collisions between reacting particles is known A) Activation energy B) Bond energy C) Kinetic energy D) Potential energy

2. The bond formed between H2OH2O and H+H+ to form the hydroxonium H3O+H3O+ is A) Dative B) Covalent C) Electrovalent D) Ionic

3. An element XX forms the following oxides X2O,XOX2O,XO and XO2.XO2. This phenomenon illustrates the law of ________. A) Conservation of mass B) Definite proportion C) Mass action D) Multiple proportion

4.. How many moles of oxygen would contain 1.204×10241.204×1024 molecules? NB: Avogadro’s constant (NA) =6.02×1023=6.02×1023 A) 1 B) 2 C) 3 D) 4

See: NECO Timetable

5. Which of the following statements about solids is correct? A) Solid particles are less orderly than those of a liquid B) Solid have lower densities than liquids C) Solid particles have greater kinetic energies than those of liquids D) Solid particles cannot be easily compressed

6. Which of the following apparatus can be used to measure a specific volume of a liquid accurately? A) Beaker B) Conical flask C) Measuring cyclinder D) Pipette

7. The general gas equation PVT=KPVT=K is a combination of A) Boyle’s and Charles’ laws B) Boyle’s and Graham’s laws C) Charles’ and Graham’s laws D) Dalton’s and Graham’s laws

8. The spreading of the scent of a flower in a garden is an example of? A) Brownian motion B) Diffusion C) Osmosis D) Tynadal effect

9. Propane and carbon (IV) oxide diffuse at the same rate because [H = 1.00, C = 12.0, O = 16.0] Options A) They are both gases B) Their molecules contain carbon C) They have the same relative molecular mass D) Both are denser than air

1O. The energy which accompanies the addition of an electron to an isolated gaseous atom is A) Atomization B) Electronegativity C) Electron affinity D) Ionization

11. A sample of hard water contains some calcium sulphate and calcium hydrogen carbonate. The total hardness may therefore be removed by A. boiling the water B. adding excess calcium hydroxide C. adding a calculated amount of calcium hydroxide D. adding sodium carbonate E. adding magnesium hydroxide

12. During the electrolysis of copper II sulphate between platinum electrodes, if litmus solution is added to the anode compartment, A. the litmus turns blue but no gas is evolved B. the litmus turns blue and oxygen is evolved C. the litmus turns blue and hydrogen is evolved D. the litmus turns red and oxygen is evolved E. the litmus turns red and then becomes colourless

13. The reaction between an organic acid and an alcohol in the presence of an acid catalyst is known as; A. saponification B. dehydration C. esterification D. hydrolysis E. hydration

14. The IUPAC names of the compounds CH3COOH and CH2=CH2 are respectively; A. acetic acid and ethane B. ethanoic acid and ethene C. methanoic acid and ethylene D. ethanol and ethene E. acetic acid and ethylene

15. If 30cm3 of oxygen diffuses through a porous pot in 7 seconds, how long will it take 60cm3 of chlorine to diffuse through the same pot, if the vapour densities of oxygen and chlorine are 16 and 36 respectively? A. 9.3 sec B. 14 sec C. 21 sec D. 28 sec E. 30.3 sec

16. When heat is absorbed during a chemical reaction, the reaction is said to be A. thermodynamic B. exothermic C. isothermal D. endothermic E. thermostatic

17. When large hydrocarbon molecules are heated at high temperature in the presence of a catalyst to give smaller molecules, the process is known as A. disintegration B. polymerization C. cracking D. degradation E. distillation

18. The pH of four solutions W, X, Y, Z are 4, 6, 8, 10 respectively, therefore A. none of these solutions is acidic B. the pH of Y is made more acidic by addition of distilled water C. Z is the most acidic solution D. W is the most acidic solution E. X is neutral

19. When each of the nitrates of Potassium, Magnesium and iron is heated, A. all the nitrates decompose to their oxides B. the nitrate of magnesium gives the nitrite and oxygen C. the nitrates of iron magnesium and iron give the oxides D. the nitrate of iron gives the nitrite and oxygen E. the nitrate of the magnesium is not decomposed

2O. Which of the following metals cannot replace hydrogen from water or steam? A. Sodium B. Magnesium C. Iron D. Calcium E. Copper

21. small quantity of solid ammonium chloride (NH4Cl) was heated gently in a test tube, the solid gradually disappears to produce two gases. Later, a white cloudy deposit was observed on the cooler part of the test tube. The ammonium chloride is said to have undergone A. distillation B. sublimation C. precipitation D. evaporation E. decomposition

22. Elements P, Q, R, S have 6, 11, 15, 17 electrons respectively, therefore, A. P will form an electrovalent bond with R B. Q will form a covalent bond with S C. R will form an electrovalent bond with S D. Q will form an electrovalent bond with S E. Q will form a covalent bond with R

23. An element X forms the following compounds with chlorine; XCl4, XCl3, XCl2. This illustrates the A. law of multiple proportions B. law of chemical proportions C. law of simple proportions D. law of conservation of mass E. law of definite proportions

24. The oxidation state of chlorine in potassium chlorate is A. +1 B. +2 C. +3 D. +5 E. +7

25. 10 When air which contains the gases Oxygen, nitrogen, carbondioxide, water vapour and the rare gases, is passed through alkaline pyrogallol and then over quicklime, the only gases left are; A. nitrogen and carbondioxide B. the rare gases C. nitrogen and oxygen D. nitrogen and the rare gases E. nitrogen, carbondioxide and the rare

26. Which of the following statements is NOT correct? A. The average kinetic energy of a gas is directly proportional to its temperature B. At constant tempearture, the volume of a gas increases as the pressure increases C. The pressure of a gas is inversely proportional to its volume D. The temperature of a gas is directly proportional to its volume E. The collisions of molecules with each other are inelastic

27. Zinc Oxide is a A. Basic Oxide B. Acidic Oxide C. Amphoteric Oxide D. Neutral Oxide E. Reactive Oxide

28. When sodium chloride and metallic sodium are each dissolved in water A. both processes are exothermic B. both processes are endothermic C. the dissolution of metallic sodium is endothermic D. the dissolution of metallic sodium is exothermic E. the dissolution of sodium chloride is explosive

29. The periodic classification of elements is an arrangement of the elements in order of their A. Atomic Weights B. Isotopic Weights C. Molecular Weights D. Atomic Numbers E. Atomic Masses

3O. In the reaction between sodium hydroxide and sulphuric acid solutions, what volume of 0.5 molar sodium hydroxide would exactly neutralise 10cm3 of 1.25 molar sulphuric acid? A. 5cm3 B. 10cm3 C. 20cm3 D. 25cm3 E. 50cm3

Recommended: How to check NECO Result

NECO Chemistry Questions And Answers 2023 (Paper 2)

Don’t worry about these NECO Chemistry Questions And Answers 2023. All you need to do is to keep on refreshing this page for the 2023 NECO Chemistry Questions And Answers for this year. It will be posted here in few minutes.

Tips on How to Pass 2023 NECO Chemistry Examinations

The following guidelines will help you pass the 2023 NECO Chemistry examination with flying colours.

Have a Target and Work Towards Actualizing it

You have decided to pass NECO Chemistry 2023 and I am sure of that. Now, the next thing you should do is set targets.

You have told yourself, “I will score A in NECO Chemistry 2023”, that’s not all. You need to plan on how to make it happen. Create a timetable and master plan to achieve your goals.

Get the Recommended Textbook on Chemistry for 2023 NECO Examination

Normally, NECO recommends books for the examination. But apart from NECO Literature in English where certain novels are compulsory, you are free to use any good Chemistry textbook to prepare for NECO 2023 exam.

Some textbooks are more difficult to understand. If you have any topic you are finding difficult to understand, then get a textbook that will simplify the topics and make life better for you.

Do not Skip Chemistry Examples and Exercise you Will Come Across While Reading:

Many candidates are fond of skipping exercises and even examples while studying textbooks. In fact, we like notebooks so much that we could ask, “can I read my notebook and pass NECO Chemistry 2023?” Don’t be scared of attempting exercises in Biology. Face the challenges.

If you have any questions about the NECO Chemistry Questions and Answers 2023 , kindly drop your question in the comment box.

Last Updated on July 25, 2023 by Admin

122 thoughts on “NECO Chemistry Questions and Answers 2023/2024 (Essay and Objectives)”

Please when will the answer come up

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WHERE IS THE ANSWER FOR THE OBJ QUESTIONS THAT IS UP THERE

2024 NECO CHEMISTRY: 2024 NECO Chemistry (Chems) Practical Verified Answers with questions (1902)

Obj & notice section, 2023 neco chemistry (chems) practical verified answers with questions password/pin/code: 1902 ..

Note that each school has its own specific endpoint value, and it is important to use the correct value for calculations. If your school has a designated endpoint value, you should replace the given value in the instructions with your school's value and perform the necessary calculations using it.

If your school intends to use the provided endpoint value, your Chemistry teacher must submit a value that is similar to the given value with minimal deviation. After replacing the endpoint value, all subsequent calculations should be recalculated accordingly.

The value obtained in question 1bi should be used to solve question 1bii, and the resulting answer should be used for question 1biii. It is essential to understand and follow these instructions as a science student.

Welcome to official 2024 Chemistry NECO answer page. We provide 2024 Chemistry NECO Questions and Answers on Essay, Theory, OBJ midnight before the exam, this is verified & correct NECO Chems Expo. NECO Chemistry Questions and Answers 2024. NECO Chems Expo for Theory & Objective (OBJ) PDF: verified & correct expo Solved Solutions, 2024 NECO Chemistry (Chems) Practical Verified Answers with questions. 2024 NECO EXAM Chemistry Questions and Answers

CLICK HERE TO VIEW ANSWER No. 1 on Chemistry

2024 NECO Chemistry (Chems) Practical Verified Answers with questions 2024 NECO CHEMISTRY: 2024 NECO Chemistry (Chems) Practical Verified Answers with questions (1902) Welcome to official 2024 Chemistry NECO answer page. We provide 2024 Chemistry NECO Questions and Answers on Essay, Theory, OBJ midnight before the exam, this is verified & correct NECO Chems Expo

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Neco Chemistry Objective & Essay Expo (15th July 2024)

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Online Password Link Answers

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Neco Chemistry Exam Schedule

From the Neco Released exam timetable document, Neco Chemistry Objective, Essay will kick start on Monday 15th July 2024.

Monday 15th July

Paper III & II: Objective & Essay – Chemistry › 10:00 am – 1:00 pm

WAEC Exam Questions and Answers

Following the change of normal routine on the pattern of exams, you can as well subscribe for Waec Exam that’s coming this August, do the needful and follow the link below : How to Get WAEC Expo Answers 2024

What is Neco Exam Objective

The National Examination Council (also known as NECO) is an examination body that is responsible for conducting the National Common Entrance Examination (NCEE), Basic Education Certificate Examination (BECE), Senior School Certificate Examination (SSCE) Internal and External for students. The exam body is currently chaired by Professor Charles Uwakwe.

How to Check NECO Result Online?

After most exams, candidates are required to check their results to enable know the level of their performance, also to check if if they can go further with the academic pursuit. To check NECO result, visit the official result checker portal. Click on Check Neco result to learn the steps in checking NECO result online.

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NECO Chemistry Questions and Answers 2022/2023 Theory & OBJ Expo

March 29, 2022

Getting NECO Chemistry Questions 2021/2022 with solved NECO chemistry answers 2021 before the exam had been a big dream for candidates looking for NECO Chemistry questions and answers in 2021

That is the reason we are sharing this NECO chemistry expo 2021 with candidates so that they will not be stranded during the exam.

Proper usage of this material will guarantee you sure insights on the kind of NECO questions for chemistry 2021 that you should expect and how to draft expo answers for them.

OBJ (Paper 1)NECO Questions and Answers for Chemistry 2021.

The chemistry questions and answers for NECO 2021 will be in two papers. The first paper (paper 1) is the OBJ (objective) and the second paper is paper 2 (theory, essay, calculations and show working).

So in this aspect, I will supply you with the basic NECO chemistry questions 2021 samples with correct NECO chemistry answers 2021 to the NECO 2021 chemistry questions and answers samples.

Check out the sample solved Questions and Answers below.

Solved Chemistry Answers
Practice Chemistry Questions and answers
Secret on how to pass NECO 2021

Sample OBJ Chemistry Questions and Answers for NECO 2021

Solved NECO Chemistry Questions and Answers 2020/2021 for Theory & OBJ. Check free expo runs for chemistry objective and essay papers..

Download NECO 2021 Syllabus for Chemistry

1. Who found the Periodic table?

Period Dickson
John Dalton

The correct answer is D. Mendeleev

2. Periodic table is arranged in ____and _____

Lanthanide and Actinide
Groups and periods
Groups and electronic configuration
Atomic number and outer shell
Transition and atomic shell

The correct answer is B. Groups and periods

3. Which of these is not a constituent of Urine.

The answer is E. Bacteria

4. Bronze is made up of _____ and _____?

Iron and copper
Tin and iron
Copper and tin
Nickel and iron
Zinc and copper

The answer is copper and tin

5. Which of the following is not a metalloids

The correct answer is D. Nickel

6. The most reactive non-metal is_____?

The correct answer is A. Fluorine

7. What is the I.U.P.A.C name of CH 3 CH 2 OH?

The correct answer is D. Ethanol

8. Which of these is not an aromatic compound

Acetophenone

The correct answer is E. Tulane

9. The chemical symbol for Silver is____?

The answer is B. Ag

10. An element with an atomic number of 16 will likely belong to group_____ on the periodic table.

The answer is E.6

11. Group 7 elements are also known as _______?

Alkali metals
Transition elements.
Alkali earth metals.

The correct answer is A. Halogens

Get answers for chemistry practical paper

Theory Paper 2, Chemistry Questions and answers 2021 Samples

These are NECO 2021 theory Chemistry Questions and answers 2021 Samples for paper 2. This is the second paper (paper 2) and it is an “essay, calculations and show working section”.

Practice these questions because they might come up in the exam.

1. a. State Faraday’s first law of electrolysis.

Faraday’s first law of electrolysis states that the mass (m) of a substance liberated at an electrode during electrolysis is directly proportional to the quantity of electricity (Q) passing through the electrolyte.

Mathematically;

Where quantity of electricity = current (I) x time (t).

i.e Q = It.

ii. Explain an electrolytic cell.

An electrolytic cell consists of a container of electrolytes with two electrodes connected to a suitable direct current supply.

2a. List 4 constituents of Air.

Carbon (iv) oxide
Rare gases.

2b. Write the IUPAC name of CH 2 OH CHOHCHO: Ans. 2, 3-Dihydroxy propanal.

3. When 4.5g of liquid water was formed by burning hydrogen gas in oxygen, -72KJ of heat was given off. Calculate the standard heat of the formation of water.

Equation of reaction.

H 2(g) + 1 / 2 O 2(g) → H 2 O(l) ∆H © f = ? KJmol -1 .

4.5g of liquid water produces -72KJ of heat

1.0g of liquid water produces – 72

= -16.0KJ of heat

Therefore, 18g of liquid water will produce: (16.0 x 18) KJ of heat = -288KJmol -1

4. Define the following terms:

Bomb calorimeter
Heat of fusion
Spontaneous reaction
Gibbs free energy.

Bomb calorimeter: A bomb calorimeter consists of a strong cylindrical steel vessel lined with enamel to prevent corrosion.

The heat of fusion: This is the heat change when one mole of solid is melted.

Entropy: Entropy is a degree of disorderliness or randomness of a system.

Spontaneous reaction: A spontaneous reaction is a reaction that occurs on its own without the assistance of an external agent.

Gibbs free energy: The free energy (G), of a chemical system is the energy that is available for doing work.

NECO Expo for Chemistry exam 2021 (Important terms)

Now that you have gotten some sample NECO chemistry theory and OBJ questions for 2021 to practice with, let me give you a quick and common expo hint for Chemistry exam 2021 (Important terms to note)

IUPAC: IUPAC means, International Union of Pure and Applied Chemistry.

Nucleus: The Nucleus is made up of Proton and neutron.

Laws of Chemical combination includes;

Law of conservation of mass
The law of definite proportions or constant composition.
Law of multiple proportions.

Chemical symbol: A chemical symbol of an element represents an atom of the element.

Radicals: Radicals are groups of an atom carrying charges that keep their identity and react as a single unit.

Empirical formula: Empirical formula is the simplest possible formula giving the ratio of atoms in a molecule of the compound.

Mole: A mole is the amount of substance that contains as many elementary entities as that in a 12g of carbon.

Isotope: An isotope occurs in elements with the same atomic number (Number of protons) but different mass numbers (because of varying numbers of neutrons).

The Avogadro’s Number (N A ) is 6.02×1023

PH scale: the PH scale is numbered from 0 – 14. From 0 to 6 indicates the degree of acidity, 7 is neutral while, above 7 to 14 indicates the degree of alkalinity.

I am sure these NECO Chemistry Questions and answers 2021 material will help you to perform better in this exam.

Please, treat the above questions as sample questions and not as the main exam questions.

Thanks a lot

you’re welcome.

Thanks for your help

Thanks so much for your help

Nice page of learning

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*NECO 2024 CHEMISTRY THEORY ANSWERS*

`ANSWER FOUR(4) QUESTIONS ONLY“`

(1b) (I) Group 17 (halogens) (II) lodine (III) lodine

(1ci) I. Calcium (Ca²⁺) II. Magnesium (Mg²⁺)

(1cii) I. lon exchange method II. Lime-soda method

(1di) (I) Methyl orange is used in the titration of a strong acid with a strong base. (II) Phenolphthalein is used in the titration of a strong base with a strong acid.

(1dii) (I) Hydrated salt: Copper(II) sulfate pentahydrate (CuSO₄.5H₂O) (II) Acidic salt: Ammonium chloride (NH₄Cl) (III) Basic salt: Sodium carbonate (Na₂CO₃)

(1ei) 2-methylbutane –> pentane –> 2,2-dimethylpropane

(1eii) (I) 1-bromo-3-methylbutane (II) 2-methylpentane

(1eiii) Benzene is used as a starting material in the production of various important chemicals such as ethylbenzene, cumene, cyclohexane, and nitrobenzene.

(1f) Given, Vapour density = 77

molecular mass of XCl₄ = Molecular mass = Vapour density x 2 = 77 x 2 = 154

Molecular mass of XCl₄ = X + 4(Atomic mass of Cl) 154 = X + 4(35.5) X = 154 – 142 X = 12

:. The relative atomic mass of X is 12. ===================================

(2ai) A molar solution (M) is a solution that contains one mole of solute (dissolved substance) per liter (dm³) of solution.

(2aii) Convert volume from cm³ to dm³: 250cm³=0.250dm³

Number of moles of Na₂CO₃ = Concentration(mol/dm³) × Volume (dm³) = 0.10mol/dm³ x 0.25 dm³ = 0.025mol

Mass of Na₂CO₃ = Number of moles x Molar mass(g/mol) = 0.025 mol x 106 g/mol = 2.65 g

(2ci) (I) Strong acids completely dissociate in water, while weak acids partially dissociate (II) Strong acids have a high tendency to donate protons, whereas weak acids have a lower tendency

(2cii) (I) Covalent compounds have low melting and boiling points (II) They are generally insoluble in water (III) Covalent compounds tend to be soft and brittle.

(2di) Diagram

(2dii) The monosaccharides contained in sucrose are glucose and fructose.

(3ai) (i) Stage 1: Production of sulfur dioxide: S(s) + O₂(g) ==> SO₂(g)

(ii) Stage 2: Conversion of sulfur dioxide to sulfur trioxide: 2SO₂(g) + O₂(g) <==> 2SO₃(g)

(iii) Stage 3: Absorption of sulfur trioxide in water to form tetraoxosulphate (VI) acid: SO₃(g) + H₂O(l) ==> H₂SO₄(l)

(3aiii) (i) Relative positions of ions in the electrochemical series. (ii) Concentration of ions in the electrolyte solution. (iii) Nature of the electrodes.

(3b) Molar mass of MgSO₄= Mg + S +4 * O Molar mass of MgSO₄= 24 + 32 + (4*16) = 24+32+64= 120g/mol

The molar concentration in mol/dm³= 0.75mol/dm³

Given the mass concentration of the hydrated salt= 184.5g/dm³

Mass concentration=molar concentration * molar mass of MgSO₄⋅XH₂O 184.5 = 0.75 * molar mass of MgSO₄⋅XH₂O Molar mass of MgSO₄⋅XH₂O= 184.5/0.75 = 246g/mol

Molar mass of MgSO₄⋅XH₂O= molar mass of MgSO₄ + X * molar mass of H₂O

246 = 120 + X * (2*1+16) 246 = 120 + X * 18 246 = 120 + 18X X = (246 – 120)/18 X = 126/18 X = 7

(3ci) Reduction refers to the process where an atom, ion, or molecule gains electrons, leading to a decrease in its oxidation number.

(3cii) The oxidizing agent in the reaction is Br₂

(3ciii) (I) Contain carbon-hydrogen bonds. (II) Often have covalent bonding. (III) Can be highly complex in structure.

(3civ) (I) Plants (e.g., olive oil, sunflower oil) (II);Animals (e.g., butter, lard) ===================================

(4ai) Allotropy is the existence of two or more different forms of the same element in the same physical state.

(4aii) Carbon

(4aiii) (I) It is used in carbonated beverages to provide fizziness. (II) It is used in fire extinguishers as it is denser than air and can displace oxygen, thereby suffocating the fire.

(4bii) Calcium reacts with oxygen to form calcium oxide (CaO): 2Ca + O₂ ==> 2CaO

Molar mass of calcium: 40g/mol Molar mass of oxygen: 16g/mol

Number of moles of Ca = 4.8g/40g/mol = 0.12mol

Number of moles of O₂ = 0.12mol (since it’s a 1:1 ratio)

Mass of oxygen required = 0.12mol x 16g/mol = 1.92g

(4ci) (I) X is Iron(III) oxide (Fe₃O₄) and Y is Hydrogen gas (H₂) (II) Equation: 3Fe + 4H₂O ==> Fe₃O₄ + 4H₂

(4cii) Yellow color (lead iodide, PbI₂)

(4ciii) Diagram

(4dii) Percentage composition of sodium in NaNO₃: Percentage of an element = (Atomic mass of the element * Number of atoms of the element/molecular mass of the compound) * 100

Molar mass of NaNO₃: Na: 23g/mol N: 14g/mol O: 16g/mol * 3 = 48g/mol

= 23 + 14 + 48 = 85 g/mol

Percentage of Na: (Mass of Na / Molar mass of NaNO₃) x 100% = (23/85) * 100 = 0.2706 x 100 = 27.06%

(4diii) (I) Ammonia (NH₃): Heavy chemical (II) Drugs: Fine chemicals (III) Sodium hydroxide (NaOH): Heavy chemical ===================================

(5ai) (I) A is NH₃ (Ammonia) and B is HCl (Hydrochloric acid). (II) Decomposition reaction

(5aiii) (I) lonic bond (II) Covalent bond (III) Metallic bond

(5bi) (I) Anhydrous Copper(II) Sulfate (CuSO₄) (II) Cobalt(II) Chloride Paper (CoCl₂)

(5bii) (I) Ensure the burette is calibrated correctly (II) Use a white tile or paper to read the meniscus clearly (III) Take readings with the eye level at the meniscus

(5cii) (I) Potassium (K): 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ (II) Magnesium (Mg): 1s² 2s² 2p⁶ 3s² (III) Oxygen (O): 1s² 2s² 2p⁴

(5di) (I) H⁺ (hydronium ion) (II) H₃O⁺ (hydronium ion)

(6ai) Ethene: C₂H₄ has a double bond between two carbon atoms. Ethyne: C₂H₂ has a triple bond between two carbon atoms.

(6aii) Polyacetylene

(6aiii) Structure of Polyethylene: (-CH=CH-)n

(6bii) Solubility of KCIO (potassium hypochlorite): Molar mass of KCIO₃: 39 + 35.5 + (3*16) = 122.5g/mol

Convert mass of KCIO₃ to moles = 4.9/122.5 = 0.04mol

Volume of water = 20cm³ = 0.02dm³

Solubility S in mol/dm³ = moles of KCIO₃/Volume of water in dm³ = 0.04/0.02 Solubility= 2.0mol/dm³

(6ci) (I) It is a colorless liquid at room temperature. (II) It has a characteristic odor. (III) It is miscible with water in all proportions.

(6di) (I) It is used in the manufacture of glass. (II) It is used in water softening and as a cleaning agent.

*COMPLETED*

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NECO 2024 Chemistry OBJ/ ESSAY Answers

NECO 2024 Chemistry (OBJ/ESSAY) Questions and Answers

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2024 NECO CHEMISTRY OBJ (OBJECTIVE) ANSWERS

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CHEMISTRY OBJ

01-10: BC**********E

11-20: DD**********D

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41-50: CABA*******D

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2024 NECO CHEMISTRY ESSAY (THEORY) ANSWERS

CHEMISTRY ESSAY

(1b) (I) Group 17 (halogens) (II) lodine (III) lodine

(1ci) I. Calcium (Ca²⁺) II. Magnesium (Mg²⁺)

(1cii) I. lon exchange method II. Lime-soda method

(1di) (I) Methyl orange is used in the titration of a strong acid with a strong base. (II) Phenolphthalein is used in the titration of a strong base with a strong acid.

(1dii) (I) Hydrated salt: Copper(II) sulfate pentahydrate (CuSO₄.5H₂O) (II) Acidic salt: Ammonium chloride (NH₄Cl) (III) Basic salt: Sodium carbonate (Na₂CO₃)

(1ei) 2-methylbutane –> pentane –> 2,2-dimethylpropane

(1eii) (I) 1-bromo-3-methylbutane (II) 2-methylpentane

(1eiii) Benzene is used as a starting material in the production of various important chemicals such as ethylbenzene, cumene, cyclohexane, and nitrobenzene.

(1f) Given, Vapour density = 77

molecular mass of XCl₄ = Molecular mass = Vapour density x 2 = 77 x 2 = 154

Molecular mass of XCl₄ = X + 4(Atomic mass of Cl) 154 = X + 4(35.5) X = 154 – 142 X = 12

:. The relative atomic mass of X is 12.

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Monday, 15th July 2024 Chemistry (Objective & Essay) 10:00am - 1:00pm

CHEMISTRY OBJ: 1-10: BBCCAEDECE 11-20: DDBCADEEAD 21-30: ACADCDDBAE 31-40: CCBCECACBA 41-50: CCBDCAEBBA 51-60: BBDDCACBCC (WITH NUMBERING) 1.B 2.B 3.C 4.C 5.A 6.E 7.D 8.E 9.C 10.E 11.D 12.D 13.B 14.C 15.A 16.D 17.E 18.E 19.A 20.D 21.A 22.C 23.A 24.D 25.C 26.D 27.D 28.B 29.A 30.E 31.C 32.C 33.B 34.C 35.E 36.C 37.A 38.C 39.B 40.A 41.C 42.C 43.B 44.D 45.C 46.A 47.E 48.B 49.B 50.A 51.B 52.B 53.D 54.D 55.C 56.A 57.C 58.B 59.C 60.C

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